What is the pH of 0.1,M,N{H_3} | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$NH _3+ H _2 O ightleftharpoons NH _4+ OH ^{-}$

$Kb =\frac{\left[ NH _4^{+}ight]\left[ OH ^{-}ight]}{\left[ NH _3ight]}$

$1.8 	imes 10^

Vedclass · Accepted Answer

$11.13$

Vedclass · Answer

$NH _3+ H _2 O ightleftharpoons NH _4+ OH ^{-}$

$Kb =\frac{\left[ NH _4^{+}ight]\left[ OH ^{-}ight]}{\left[ NH _3ight]}$

$1.8 	imes 10^{-5}=\frac{ x ^2}{0.1}$

$\Rightarrow x =\sqrt{1.8 	imes 10^{-6}}$

$=1.34 	imes 10^{-3}$

$	herefore\left[ OH ^{-}ight]\left[ H ^{+}ight]=1.34 	imes 10^{-3}\left[ H ^{+}ight]=10^{-14}$

$\Rightarrow pH =11.13$

What is the $pH$ of $0.1\,M\,N{H_3}$

Similar Questions

The $pH$ of $ 0.1 \,M$ solution of a weak monoprotic acid $1\%$ ionized is

What is the $pH$ of solution of $7$ $gm$ $N{H_4}OH$ per $500$ $mL$ ? ( ${K_b}$ of $N{H_4}OH 1.8 \times {10^{ - 5}}$, Molecular moles of $N{H_4}OH$ is $35\,g\,mo{l^{ - 1}}$ )

$p{K_a}$ of a weak acid is defined as

$0.2$ molar solution of formic acid is ionized $3.2\%$. Its ionization constant is

A solution of sodium borate has a $pH$ of approximately