What is the percentage of Fe^{+3} among catio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the amount of $Fe^{+3}$ be $x$ and $Fe^{+2}$ be $(0.93 - x)$.The total charge must be zero for the neutral compound $Fe_{0.93}O_{1.00}$.$3x +

Vedclass · Accepted Answer

$14/93 	imes 100$

Vedclass · Answer

(B) Let the amount of $Fe^{+3}$ be $x$ and $Fe^{+2}$ be $(0.93 - x)$.The total charge must be zero for the neutral compound $Fe_{0.93}O_{1.00}$.$3x + 2(0.93 - x) - 2 = 0$$3x + 1.86 - 2x - 2 = 0$$x = 0.14$The fraction of $Fe^{+3}$ ions among total iron cations is $\frac{0.14}{0.93}$.Therefore,the percentage of $Fe^{+3}$ is $\frac{0.14}{0.93} 	imes 100 = \frac{14}{93} 	imes 100$.

What is the percentage of $Fe^{+3}$ among cations in $Fe_{0.93}O_{1.00}$?

Similar Questions

In spite of long-range order in the arrangement of particles,why are the crystals usually not perfect?

Explain the following term with a suitable example:
$(iii)$ Interstitials

If $NaCl$ is doped with $10^{-3} \, mol \%$ of $SrCl_{2}$,what is the concentration of cation vacancies?

Schottky defect in crystals is observed when

Select the incorrect statement for Schottky defect.

Vedclass Test Series

Exam Paper Generator

Online Exam Module