What is the oxidation number of N in HNO_4? | vedclass

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(B) In $HNO_4$ (peroxynitric acid),the structure contains a peroxy linkage $(-O-O-)$.The oxidation state of $H$ is $+1$.There are two oxygen atoms in

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$+5$

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(B) In $HNO_4$ (peroxynitric acid),the structure contains a peroxy linkage $(-O-O-)$.The oxidation state of $H$ is $+1$.There are two oxygen atoms in the peroxy linkage with an oxidation state of $-1$ each,and two other oxygen atoms with an oxidation state of $-2$ each.Let the oxidation number of $N$ be $x$.Sum of oxidation numbers $= 1 + x + 2(-1) + 2(-2) = 0$$1 + x - 2 - 4 = 0$$x - 5 = 0$$x = +5$

What is the oxidation number of $N$ in $HNO_4$?

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