Which of the following statements is not true about borax?
- AThe molecular formula is $Na_2B_4O_7 \cdot 10H_2O$.
- BCrystalline borax contains a tetranuclear unit $[B_4O_5(OH)_4]^{2-}$.
- CIt hydrolyses to give an acidic solution.
- DIt is a white crystalline solid.
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Similar Questions
In the structure of diborane $(B_2H_6)$,the number of $2$-centre-$2$-electron $(2c-2e)$ bonds is $X$ and the number of $3$-centre-$2$-electron $(3c-2e)$ bonds is $Y$. The value of $(X+Y)$ is:
The correct formula of borax is $Na_2[B_4O_5(OH)_4] \cdot 8H_2O$. If the formula is represented as $Na_2[B_4O_5(OH)_x] \cdot yH_2O$,then the sum of $x$ and $y$ is:
Which of the following statements is $NOT$ correct for potash alum?
Medium
View SolutionBorax is converted into crystalline boron by the following steps :
$Borax$ $\xrightarrow{HCl} (X)$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow{\Delta, Y} B$
Identify $X$ and $Y$ respectively.
$Borax$ $\xrightarrow{HCl} (X)$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow{\Delta, Y} B$
Identify $X$ and $Y$ respectively.
Identify the correct statements:
$i$. Oxidation of $NaBH_4$ with $I_2$ gives $B_2H_6$
$ii$. $B_2H_6$ burns in oxygen and releases an enormous amount of energy
$iii$. $B_2H_6$ on hydrolysis gives a tribasic acid
$i$. Oxidation of $NaBH_4$ with $I_2$ gives $B_2H_6$
$ii$. $B_2H_6$ burns in oxygen and releases an enormous amount of energy
$iii$. $B_2H_6$ on hydrolysis gives a tribasic acid
DifficultAP EAMCET 2024
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