What is formed when benzoyl chloride reacts with aniline in the presence of sodium hydroxide?

The decreasing order of basicity is:
$(1) \ CH_3CONH_2$
$(2) \ CH_3CH_2NH_2$
$(3) \ PhCH_2CONH_2$

An organic compound $[A]$ $(C_4H_{11}N)$ shows optical activity and gives $N_2$ gas on treatment with $HNO_2$. The compound $[A]$ reacts with $PhSO_2Cl$ producing a compound which is soluble in $KOH$. The structure of $A$ is:

The correct order of basicity of the various nitrogen atoms in $LSD$ is:

The correct order of basic strength is:

Give the structure of $A$ in the following reaction.
$2\text{-Nitro-4-methylaniline} \xrightarrow[(ii) \ H_3PO_2, H_2O]{(i) NaNO_2 + HCl, 273 - 278 \ K} A$.