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(B) The intensity of solar radiation on Earth is approximately $I = 1.4 	imes 10^3 \, W/m^2$.The radiation pressure $P$ exerted on a perfectly absorb

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$4.6 	imes 10^{-10} \, N$

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(B) The intensity of solar radiation on Earth is approximately $I = 1.4 	imes 10^3 \, W/m^2$.The radiation pressure $P$ exerted on a perfectly absorbing surface is given by $P = I/c$,where $c = 3 	imes 10^8 \, m/s$ is the speed of light.$P = (1.4 	imes 10^3) / (3 	imes 10^8) = 4.67 	imes 10^{-6} \, N/m^2$.The area $A = 10 \, cm^2 = 10 	imes 10^{-4} \, m^2 = 10^{-3} \, m^2$.The force $F = P 	imes A = (4.67 	imes 10^{-6}) 	imes (10^{-3}) = 4.67 	imes 10^{-9} \, N$.Given the standard approximation for solar constant,the closest value is $4.6 	imes 10^{-9} \, N$. (Note: Assuming the question implies $10^{-9} \, N$ range).

What is the force exerted on a surface having an area of $10\, cm^2$ due to the radiation of the Sun?

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