What is compressibility factor $(Z)$? Explain $(i)$ deviation factor $(Z = 1)$,$(ii)$ $Z > 1$,$(iii)$ $Z < 1$,$(iv)$ deviation graph,and $(v)$ the relation between molar volume and $Z$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) Compressibility factor $(Z)$ is defined as the ratio of the product of pressure and volume to the product of the number of moles,gas constant,and temperature: $Z = \frac{pV}{nRT}$.
$(i)$ For an ideal gas,$Z = 1$ at all temperatures and pressures,as it follows the equation $pV = nRT$. On a $Z$ vs $p$ graph,this is represented by a horizontal line parallel to the pressure axis.
$(ii)$ $Z > 1$ (Positive deviation): This occurs at high pressures where real gases are less compressible than ideal gases. Gases like $H_2$ and $He$ show $Z > 1$ at all pressures because intermolecular forces are negligible compared to the volume occupied by molecules.
$(iii)$ $Z < 1$ (Negative deviation): This occurs at intermediate pressures where attractive forces dominate,making the gas more compressible than an ideal gas. Gases like $CH_4$ and $CO_2$ show this behavior at lower pressures.
$(iv)$ The deviation graph plots $Z$ on the $y$-axis against $p$ on the $x$-axis. The ideal gas line is a horizontal line at $Z = 1$. Real gases show curves that deviate from this line depending on pressure and temperature.
$(v)$ The relation between molar volume and $Z$ is given by $Z = \frac{V_{real}}{V_{ideal}}$,where $V_{real}$ is the actual molar volume and $V_{ideal} = \frac{RT}{p}$ is the molar volume of an ideal gas at the same temperature and pressure.

Explore More

Similar Questions

In the van der Waals equation for real gases,which of the following terms represents the correction for intermolecular forces?

The cooling in a refrigerator is due to

The compressibility factor for a van der Waal gas at high pressure is

For a real gas at $25^{\circ} C$ temperature and high pressure $(99 \ bar)$,the value of the compressibility factor is $2$. The value of the Van der Waals constant '$b$' is $\times 10^{-2} \ L \ mol^{-1}$. (Nearest integer) (Given $R = 0.083 \ L \ bar \ K^{-1} \ mol^{-1}$)

Explain real gases showing deviations from ideal gas with correction of pressure and volume and derive van der Waals equation.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo