What is association? What is dissociation?
(N/A) Association: It is the process in which two or more molecules of a solute combine to form a larger single molecule. This leads to a decrease in the total number of particles in the solution,resulting in a van't Hoff factor $(i < 1)$. For example,the dimerization of acetic acid in benzene.
Dissociation: It is the process in which a solute molecule splits into two or more simpler ions or smaller molecules when dissolved in a solvent. This leads to an increase in the total number of particles in the solution,resulting in a van't Hoff factor $(i > 1)$. For example,the dissociation of $NaCl$ into $Na^+$ and $Cl^-$ ions in water.
Dissociation: It is the process in which a solute molecule splits into two or more simpler ions or smaller molecules when dissolved in a solvent. This leads to an increase in the total number of particles in the solution,resulting in a van't Hoff factor $(i > 1)$. For example,the dissociation of $NaCl$ into $Na^+$ and $Cl^-$ ions in water.
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Similar Questions
$A$ $0.5\%$ solution of potassium chloride was found to freeze at $-0.24^{\circ} C$. The percentage dissociation of potassium chloride is .... (Nearest integer)
(Molal depression constant for water is $1.80\, K\, kg\, mol^{-1}$ and molar mass of $KCl$ is $74.6\, g\, mol^{-1}$)
(Molal depression constant for water is $1.80\, K\, kg\, mol^{-1}$ and molar mass of $KCl$ is $74.6\, g\, mol^{-1}$)
DifficultJEE MAIN 2022
View SolutionOne mole of a solute $A$ is dissolved in a given volume of a solvent. The association of the solute takes place according to $nA \rightleftharpoons (A)_n$. The Van't Hoff factor $i$ is expressed as:
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View SolutionThe values of observed and calculated molecular weight of silver nitrate are $90$ and $170$ respectively. The degree of dissociation of silver nitrate is ......... $\%$.
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View SolutionAssertion : The molecular weight of acetic acid determined by depression in freezing point method in benzene and water was found to be different.
Reason : Water is polar and benzene is nonpolar.
Reason : Water is polar and benzene is nonpolar.
MediumAIIMS 2005
View Solution$2 \ g$ of benzoic acid $(M_w = 122 \ g/mol)$ dissolved in $25 \ g$ of $C_6H_6$ shows a depression in freezing point equal to $1.62 \ K$. Given $K_f (C_6H_6) = 4.9 \ K \ kg \ mol^{-1}$. If the acid forms a dimer in the solution,then the percentage association of the acid is $......... \%$.
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