Class 12Chemistry8-2.Carboxylic acids and Their derivativeProperties of Carboxylic Acids and Their Derivatives
MediumWhat is a soft soap?
Soaps are sodium or potassium salts of long-chain fatty acids,such as palmitic acid $(C_{15}H_{31}COOH)$,stearic acid $(C_{17}H_{35}COOH)$,and oleic acid $(C_{17}H_{33}COOH)$.
Potassium salts of these fatty acids are known as soft soaps. They are more soluble in water and are used in shaving creams and shampoos.
The reaction for the preparation of potassium stearate (a soft soap) is:
$(C_{17}H_{35}COO)_3C_3H_5 + 3KOH \rightarrow 3C_{17}H_{35}COOK + C_3H_5(OH)_3$
(Glyceryl ester of stearic acid + Potassium hydroxide $\rightarrow$ Potassium stearate + Glycerol)
Potassium salts of these fatty acids are known as soft soaps. They are more soluble in water and are used in shaving creams and shampoos.
The reaction for the preparation of potassium stearate (a soft soap) is:
$(C_{17}H_{35}COO)_3C_3H_5 + 3KOH \rightarrow 3C_{17}H_{35}COOK + C_3H_5(OH)_3$
(Glyceryl ester of stearic acid + Potassium hydroxide $\rightarrow$ Potassium stearate + Glycerol)
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Similar Questions
The major product formed by the nitration of benzoic acid is $......$.
Medium
View SolutionMatch the following:
Column-$1$ (Acid) Column-$2$ ($pK_a$ value) $A. CH_3COOH$ $I. 0.23$ $B. F_3CCOOH$ $II. 3.41$ $C. \text{Benzoic acid}$ $III. 4.19$ $D. p\text{-Nitrobenzoic acid}$ $IV. 4.76$
The correct match is:
| Column-$1$ (Acid) | Column-$2$ ($pK_a$ value) |
|---|---|
| $A. CH_3COOH$ | $I. 0.23$ |
| $B. F_3CCOOH$ | $II. 3.41$ |
| $C. \text{Benzoic acid}$ | $III. 4.19$ |
| $D. p\text{-Nitrobenzoic acid}$ | $IV. 4.76$ |
The correct match is:
DifficultTS EAMCET 2021
View SolutionThe major product $H$ in the given reaction sequence is:
$CH_3-CH_2-CO-CH_3$ $\xrightarrow{CN^-} G$ $\xrightarrow{95\% \ H_2SO_4, \Delta} H$
$CH_3-CH_2-CO-CH_3$ $\xrightarrow{CN^-} G$ $\xrightarrow{95\% \ H_2SO_4, \Delta} H$
Arrange the following in the increasing order of their acidic strength: $CH_{3}COOH, CH_{2}ClCOOH, CHCl_{2}COOH, CCl_{3}COOH$.
Easy
View Solution$CH_3COOH$ when reacts with $C_2H_5OH$ gives a product. The same product is obtained by which reaction?
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