What is A in the following reaction?C_6H_5-CH | vedclass

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(A) The reaction is an electrophilic addition of $HCl$ to an alkene,which follows Markovnikov's rule.According to Markovnikov's rule,the electrophile

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$C_6H_5-CH_2-CH(Cl)-CH_3$

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(A) The reaction is an electrophilic addition of $HCl$ to an alkene,which follows Markovnikov's rule.According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon atom of the double bond that has more hydrogen atoms,and the nucleophile $(Cl^-)$ adds to the carbon atom that has fewer hydrogen atoms.In the reactant $C_6H_5-CH_2-CH=CH_2$ (allylbenzene),the double bond is between $C_2$ and $C_3$ of the allyl group.The $CH$ group has one hydrogen atom,and the $CH_2$ group has two hydrogen atoms.Therefore,$H^+$ adds to the terminal $CH_2$ group,and $Cl^-$ adds to the $CH$ group.The product formed is $C_6H_5-CH_2-CH(Cl)-CH_3$ ($1$-phenyl$-2-$chloropropane).

What is $A$ in the following reaction?
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$

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What is $A$ in the following reaction?$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$