What happens when H_{3}PO_{3} is heated? | vedclass

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(A) $H_{3}PO_{3},$ on heating,undergoes a disproportionation reaction to form $PH_{3}$ and $H_{3}PO_{4}$.The oxidation state of $P$ in $H_{3}PO_{3}$ i

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$PH_{3}$ and $H_{3}PO_{4}$ are formed.

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(A) $H_{3}PO_{3},$ on heating,undergoes a disproportionation reaction to form $PH_{3}$ and $H_{3}PO_{4}$.The oxidation state of $P$ in $H_{3}PO_{3}$ is $+3$.The oxidation state of $P$ in $PH_{3}$ is $-3$ (reduction).The oxidation state of $P$ in $H_{3}PO_{4}$ is $+5$ (oxidation).Since the oxidation state of the same element increases and decreases simultaneously,it is a disproportionation reaction.The balanced chemical equation is:$4H_{3}PO_{3} \xrightarrow{\Delta} 3H_{3}PO_{4} + PH_{3}$

What happens when $H_{3}PO_{3}$ is heated?

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