What happens to the resistance of a conductor | vedclass

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(B) The resistance $R$ of a conductor is directly proportional to its length $l$,given by the formula $R = \rho \frac{l}{A}$,where $\rho$ is the resis

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It becomes half

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(B) The resistance $R$ of a conductor is directly proportional to its length $l$,given by the formula $R = \rho \frac{l}{A}$,where $\rho$ is the resistivity and $A$ is the cross-sectional area.Since $R \propto l$,if the length $l$ is reduced to half $(l' = l/2)$,the new resistance $R'$ will be $R' = \rho \frac{l/2}{A} = \frac{1}{2} R$.Therefore,the resistance reduces to half of its original value.

What happens to the resistance of a conductor when the length of the conductor is reduced to half?

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