What are soaps? Why do they form scum with hard water?
(N/A) Soaps are defined as the sodium or potassium salts of long-chain carboxylic acids (higher fatty acids).
When soap is added to hard water,the calcium $(Ca^{2+})$ and magnesium $(Mg^{2+})$ ions present in the water react with the soap molecules.
This reaction results in the formation of insoluble precipitates known as scum (calcium or magnesium stearate).
Because these insoluble salts do not dissolve,they interfere with the cleaning action of soap and form a sticky residue.
When soap is added to hard water,the calcium $(Ca^{2+})$ and magnesium $(Mg^{2+})$ ions present in the water react with the soap molecules.
This reaction results in the formation of insoluble precipitates known as scum (calcium or magnesium stearate).
Because these insoluble salts do not dissolve,they interfere with the cleaning action of soap and form a sticky residue.
Explore More
Similar Questions
Which biopolymer was first used for post-operative stitches?
Easy
View SolutionExplain why washing clothes with hard water is not effective.
Easy
View SolutionWhich of the following are correct structural isomers of butane $(C_4H_{10})$?
$(i)$ $n$-butane: $CH_3-CH_2-CH_2-CH_3$
(ii) Isobutane ($2$-methylpropane): $CH_3-CH(CH_3)-CH_3$
(iii) Cyclobutane: $A$ four-carbon ring structure $(C_4H_8)$
(iv) Ethane dimer: Not a valid isomer of butane.
$(i)$ $n$-butane: $CH_3-CH_2-CH_2-CH_3$
(ii) Isobutane ($2$-methylpropane): $CH_3-CH(CH_3)-CH_3$
(iii) Cyclobutane: $A$ four-carbon ring structure $(C_4H_8)$
(iv) Ethane dimer: Not a valid isomer of butane.
Medium
View SolutionButanone is a four-carbon compound with the functional group:
Easy
View Solution$A$ compound $C$ (molecular formula $C_2H_4O_2$) reacts with $Na$ metal to form a compound $R$ and evolves a gas which burns with a pop sound. Compound $C$ on treatment with an alcohol $A$ in the presence of an acid forms a sweet-smelling compound $S$ (molecular formula $C_3H_6O_2$). On addition of $NaOH$ to $C$,it also gives $R$ and water. $S$ on treatment with $NaOH$ solution gives back $R$ and $A$. Identify $C$,$R$,$A$,$S$ and write down the reactions involved.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo