What are Y and Z in the following reaction se | vedclass

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(D) The reaction sequence is as follows:$1$. $C_2H_4 + HBr ightarrow CH_3CH_2Br$ $(W)$$2$. $W + Mg / 	ext{dry ether} ightarrow CH_3CH_2MgBr$$3$.

Vedclass · Accepted Answer

$Y - NaOH / 	ext{electrolysis}; Z - CH_3CH_2CH_2CH_3$

Vedclass · Answer

(D) The reaction sequence is as follows:$1$. $C_2H_4 + HBr ightarrow CH_3CH_2Br$ $(W)$$2$. $W + Mg / 	ext{dry ether} ightarrow CH_3CH_2MgBr$$3$. $CH_3CH_2MgBr + CO_2 \xrightarrow{H_3O^+} CH_3CH_2COOH$ $(X)$$4$. $CH_3CH_2COOH$ undergoes Kolbe's electrolysis $(Y)$ to form $CH_3CH_2CH_2CH_3$ $(Z)$.$5$. $W + Na / 	ext{dry ether}$ (Wurtz reaction) also forms $CH_3CH_2CH_2CH_3$ $(Z)$.Thus,$Y$ is electrolysis and $Z$ is $CH_3CH_2CH_2CH_3$.

What are $Y$ and $Z$ in the following reaction sequence?

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