What are A and B in the following reaction se | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction sequence is as follows:$1$. $CH_3COOH$ reacts with $P_2O_5$ under heating $(\Delta)$ to form acetic anhydride $(X)$ via dehydration.$

Vedclass · Accepted Answer

$A = P_2O_5, \Delta; B = 	ext{2-acetoxybenzoic acid}$

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. $CH_3COOH$ reacts with $P_2O_5$ under heating $(\Delta)$ to form acetic anhydride $(X)$ via dehydration.$2$. Acetic anhydride $(X)$ then reacts with salicylic acid $(Y)$ in the presence of an acid catalyst $(H^ )$ to undergo acetylation of the phenolic $-OH$ group.$3$. This reaction produces $2-	ext{acetoxybenzoic acid}$,commonly known as aspirin $(B)$,which acts as an analgesic drug.Therefore,$A = P_2O_5, \Delta$ and $B = 	ext{2-acetoxybenzoic acid}$.

What are $A$ and $B$ in the following reaction sequence?
$CH_3COOH$ $\xrightarrow{A} X$ $\xrightarrow[H^{+}]{Y} \underset{\text{(Analgesic drug)}}{B}$

Similar Questions

In the reaction,the product $D$ is:
$CH_2=CH_2$ $\xrightarrow{Br_2/CCl_4} A$ $\xrightarrow{KCN} B$ $\xrightarrow{H_3O^{+}} C$ $\xrightarrow{\Delta} D$

In the presence of an iodine catalyst,chlorine reacts with acetic acid to form:

In the reaction $2CH_3COOH \xrightarrow[300^\circ C]{MnO} A$,the product $A$ is:

Which of the following compounds is used as a food preservative?

Consider the following molecules and statements related to them:
$(a)$ $(B)$ is more likely to be crystalline than $(A)$
$(b)$ $(B)$ has a higher boiling point than $(A)$
$(c)$ $(B)$ dissolves more readily than $(A)$ in water.
Identify the correct option from below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What are $A$ and $B$ in the following reaction sequence?$CH_3COOH$ $\xrightarrow{A} X$ $\xrightarrow[H^{+}]{Y} \underset{\text{(Analgesic drug)}}{B}$