What are A, B, C and D in the following cross | vedclass

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(A) The reaction is a cross-aldol condensation between propanal $(CH_3CH_2CHO)$ and ethanal $(CH_3CHO)$ in the presence of $NaOH$ followed by heating

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(A) The reaction is a cross-aldol condensation between propanal $(CH_3CH_2CHO)$ and ethanal $(CH_3CHO)$ in the presence of $NaOH$ followed by heating $(\Delta)$.This reaction produces four possible $\alpha,\beta$-unsaturated aldehydes:$1$. Self-aldol of ethanal: $2CH_3CHO \rightarrow CH_3CH=CHCHO$ (But$-2-$enal).$2$. Self-aldol of propanal: $2CH_3CH_2CHO \rightarrow CH_3CH_2CH=C(CH_3)CHO$ ($2$-methylpent$-2-$enal).$3$. Cross-aldol (propanal as donor,ethanal as acceptor): $CH_3CH_2CHO + CH_3CHO \rightarrow CH_3CH_2CH=CHCHO$ (Pent$-2-$enal).$4$. Cross-aldol (ethanal as donor,propanal as acceptor): $CH_3CHO + CH_3CH_2CHO \rightarrow CH_3CH=C(CH_3)CHO$ ($2$-methylbut$-2-$enal).Thus,the four products are $CH_3CH=CHCHO$,$CH_3CH_2CH=C(CH_3)CHO$,$CH_3CH_2CH=CHCHO$,and $CH_3CH=C(CH_3)CHO$.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

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