What are X and Y respectively in the followin | vedclass

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(C) The conversion of toluene $(C_6H_5CH_3)$ to benzoic acid $(C_6H_5CO_2H)$ requires strong oxidation,which is achieved using alkaline $KMnO_4$ follo

Vedclass · Accepted Answer

$X = (i) \ KMnO_4 / OH^{-}, \Delta, (ii) \ H_3O^{+}$; $Y = (i) \ B_2H_6, (ii) \ H_3O^{+}$

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(C) The conversion of toluene $(C_6H_5CH_3)$ to benzoic acid $(C_6H_5CO_2H)$ requires strong oxidation,which is achieved using alkaline $KMnO_4$ followed by acidic workup $(H_3O^{+})$.Thus,$X = (i) \ KMnO_4 / OH^{-}, \Delta, (ii) \ H_3O^{+}$.The reduction of benzoic acid to benzyl alcohol $(C_6H_5CH_2OH)$ is selectively performed by diborane $(B_2H_6)$ followed by acidic workup $(H_3O^{+})$,as $B_2H_6$ does not reduce the aromatic ring.Thus,$Y = (i) \ B_2H_6, (ii) \ H_3O^{+}$.Therefore,the correct option is $C$.

What are $X$ and $Y$ respectively in the following reaction sequence?
$C_6H_5CH_3$ $\xrightarrow{X} C_6H_5CO_2H$ $\xrightarrow{Y} C_6H_5CH_2OH$

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What are $X$ and $Y$ respectively in the following reaction sequence?$C_6H_5CH_3$ $\xrightarrow{X} C_6H_5CO_2H$ $\xrightarrow{Y} C_6H_5CH_2OH$