What kV potential is to be applied on an X-ra | vedclass

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(A) The minimum wavelength of emitted $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Substituting the values $h = 6.625 	imes 10^

Vedclass · Accepted Answer

$12.42$

Vedclass · Answer

(A) The minimum wavelength of emitted $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Substituting the values $h = 6.625 	imes 10^{-34} 	ext{ J-s}$, $c = 3 	imes 10^8 	ext{ m/s}$, and $e = 1.6 	imes 10^{-19} 	ext{ C}$, we get:$\lambda_{\min} = \frac{12400}{V} 	ext{ Å}$ (where $V$ is in volts).Given $\lambda_{\min} = 1 	ext{ Å}$, we have $1 = \frac{12400}{V}$.Therefore, $V = 12400 	ext{ V} = 12.4 	ext{ kV}$.Comparing this with the given options, the closest value is $12.42 	ext{ kV}$.

What $kV$ potential is to be applied on an $X$-ray tube so that the minimum wavelength of emitted $X$-rays may be $1 \text{ Å}$? $(h = 6.625 \times 10^{-34} \text{ J-s})$

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