The wavelength of a 1 ;keV photon is 1.24 tim | vedclass

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Question

(B) The energy of a photon is given by the relation $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.Given energy $E = 1 \;MeV = 1

Vedclass · Accepted Answer

$2.4 	imes 10^{20} \;Hz$

Vedclass · Answer

(B) The energy of a photon is given by the relation $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.Given energy $E = 1 \;MeV = 1 	imes 10^6 \;eV = 10^6 	imes 1.6 	imes 10^{-19} \;J = 1.6 	imes 10^{-13} \;J$.Planck's constant $h \approx 6.63 	imes 10^{-34} \;J \cdot s$.Using the formula $
u = \frac{E}{h}$:$
u = \frac{1.6 	imes 10^{-13} \;J}{6.63 	imes 10^{-34} \;J \cdot s} \approx 0.241 	imes 10^{21} \;Hz = 2.41 	imes 10^{20} \;Hz$.Thus,the frequency is approximately $2.4 	imes 10^{20} \;Hz$.

The wavelength of a $1 \;keV$ photon is $1.24 \times 10^{-9} \;m$. What is the frequency of a $1 \;MeV$ photon?

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