Water rises to a height of 16.3 , cm in a cap | vedclass

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(B) The height to which water rises in a capillary tube is given by $h = \frac{2T \cos 	heta}{r ho g}$.When the tube is cut at a height $h' = 12 \,

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water will stay at a height of $12 \, cm$ in the capillary tube

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(B) The height to which water rises in a capillary tube is given by $h = \frac{2T \cos 	heta}{r ho g}$.When the tube is cut at a height $h' = 12 \, cm$ (which is less than the original rise $h = 16.3 \, cm$),the water will rise to the top of the cut tube.It will not overflow because the radius of curvature of the meniscus will adjust to satisfy the condition $h \cdot R = 	ext{constant}$.Specifically,the meniscus will become more convex (the radius of curvature $R$ increases) such that the pressure balance is maintained at the new height of $12 \, cm$.Therefore,the water will stay at the top of the tube at a height of $12 \, cm$ without overflowing.

Water rises to a height of $16.3 \, cm$ in a capillary tube of height $18 \, cm$ above the water level. If the tube is cut at a height of $12 \, cm$ above the water level,then:

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