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(A) According to the equation of continuity,for an incompressible fluid in streamline flow,the product of the cross-sectional area $A$ and velocity $v

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velocity is max and pressure is min

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(A) According to the equation of continuity,for an incompressible fluid in streamline flow,the product of the cross-sectional area $A$ and velocity $v$ is constant $(A_1v_1 = A_2v_2)$.At the narrowest part of the pipe,the cross-sectional area $A$ is minimum,which implies that the velocity $v$ must be maximum.According to Bernoulli's theorem for horizontal flow,the sum of pressure energy and kinetic energy per unit volume remains constant:$p + \frac{1}{2} ho v^2 = 	ext{constant}$Since the velocity $v$ is maximum at the narrowest part,the pressure $p$ must be minimum to keep the sum constant.Therefore,at the narrowest part,velocity is maximum and pressure is minimum.

Water is flowing through a horizontal pipe in streamline flow. At the narrowest part of the pipe,

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