Water is conveyed through a uniform tube of 8 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Diameter $d = 8 	ext{ cm}$,so radius $r = 4 	ext{ cm} = 4 	imes 10^{-2} 	ext{ m}$.Length $l = 3140 	ext{ m}$.Rate of flow $Q = 2 	ime

Vedclass · Accepted Answer

$6.25 	imes 10^3 	ext{ N/m}^2$

Vedclass · Answer

(A) Given: Diameter $d = 8 	ext{ cm}$,so radius $r = 4 	ext{ cm} = 4 	imes 10^{-2} 	ext{ m}$.Length $l = 3140 	ext{ m}$.Rate of flow $Q = 2 	imes 10^{-3} 	ext{ m}^3/	ext{s}$.Viscosity $\eta = 10^{-3} 	ext{ SI units}$.According to Poiseuille's equation for laminar flow in a pipe:$Q = \frac{\pi P r^4}{8 \eta l}$Rearranging for pressure $P$:$P = \frac{Q(8 \eta l)}{\pi r^4}$Substituting the values:$P = \frac{2 	imes 10^{-3} 	imes 8 	imes 10^{-3} 	imes 3140}{3.14 	imes (4 	imes 10^{-2})^4}$$P = \frac{16 	imes 3140 	imes 10^{-6}}{3.14 	imes 256 	imes 10^{-8}}$$P = \frac{3140 	imes 10^2}{3.14 	imes 16}$$P = \frac{1000 	imes 10^2}{16} = \frac{10^5}{16} = 6.25 	imes 10^3 	ext{ N/m}^2$.

Water is conveyed through a uniform tube of $8 \text{ cm}$ in diameter and $3140 \text{ m}$ in length at the rate of $2 \times 10^{-3} \text{ m}^3/\text{s}$. The pressure required to maintain the flow is (Viscosity of water $= 10^{-3} \text{ SI units}$):

Similar Questions

What is turbulent flow? Give its illustrations.

The volume of a liquid is proportional to......,given its density $\rho$,viscosity $\eta$ and $t$ the time of flow through a capillary tube of length $L$ and radius $R$,with a pressure difference $p$ across its ends.

Two capillary tubes of the same length but different radii $r_1$ and $r_2$ are fitted in parallel to the bottom of a vessel. The pressure head is $P$. What should be the radius of a single tube that can replace the two tubes so that the rate of flow is the same as before?

Two different liquids are flowing in two tubes of equal radius. The ratio of coefficients of viscosity of liquids is $52:49$ and the ratio of their densities is $13:1$,then the ratio of their critical velocities will be

If it takes $5\,minutes$ to fill a $15\,litre$ bucket from a water tap of diameter $\frac{2}{\sqrt{\pi}}\,cm$,then the Reynolds number for the flow is (density of water $= 10^3\,kg/m^3$ and viscosity of water $= 10^{-3}\,Pa\cdot s$) close to

Vedclass Test Series

Exam Paper Generator

Online Exam Module