Water falls from a height of 60,m at the rate | vedclass

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(C) The potential energy available per unit time is given by the power formula: $P_{in} = \frac{mgh}{t} = \left(\frac{m}{t}\right)gh$.Given $\frac{m}{

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(C) The potential energy available per unit time is given by the power formula: $P_{in} = \frac{mgh}{t} = \left(\frac{m}{t}ight)gh$.Given $\frac{m}{t} = 15\,kg/s$,$h = 60\,m$,and $g = 10\,m/s^2$.$P_{in} = 15 	imes 10 	imes 60 = 9000\,W = 9\,kW$.The losses due to frictional forces are $10\%$,so the efficiency is $90\%$.Generated power $P_{out} = P_{in} 	imes (1 - 0.10) = 9\,kW 	imes 0.9 = 8.1\,kW$.

Water falls from a height of $60\,m$ at the rate of $15\,kg/s$ to operate a turbine. The losses due to frictional forces are $10\%$ of energy. How much power is generated by the turbine in $kW$ $(g = 10\,m/s^2)$?

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