Vessels A and B contain mixtures of milk and | vedclass

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(C) Using the method of alligation,we consider the fraction of milk in each mixture.In vessel $A$,the fraction of milk is $\frac{4}{4+5} = \frac{4}{9}

Vedclass · Accepted Answer

$5:2$

Vedclass · Answer

(C) Using the method of alligation,we consider the fraction of milk in each mixture.In vessel $A$,the fraction of milk is $\frac{4}{4+5} = \frac{4}{9}$.In vessel $B$,the fraction of milk is $\frac{5}{5+1} = \frac{5}{6}$.The required fraction of milk in the final mixture is $\frac{5}{5+4} = \frac{5}{9}$.Applying the alligation rule:Difference between milk in $B$ and final mixture: $\frac{5}{6} - \frac{5}{9} = \frac{15-10}{18} = \frac{5}{18}$.Difference between milk in $A$ and final mixture: $\frac{5}{9} - \frac{4}{9} = \frac{1}{9}$.The ratio of quantities taken from $A$ and $B$ is $\frac{5}{18} : \frac{1}{9}$.Multiplying both sides by $18$,we get $5 : 2$.

Vessels $A$ and $B$ contain mixtures of milk and water in the ratios $4:5$ and $5:1$ respectively. In what ratio should quantities of mixture be taken from $A$ and $B$ to form a mixture in which milk to water is in the ratio $5:4$?

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