Verify by calculating that:(a) 5 , mol of CO_ | vedclass

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(D) Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \, g \, mol^{-1}$.Mass of $5 \, mol$ of $CO_2 = 5 	imes 44 = 220 \, g$.Molar mass of $H_2O = (2 	i

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$90 \, g, 3:5$

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(D) Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \, g \, mol^{-1}$.Mass of $5 \, mol$ of $CO_2 = 5 	imes 44 = 220 \, g$.Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \, g \, mol^{-1}$.Mass of $5 \, mol$ of $H_2O = 5 	imes 18 = 90 \, g$.Since $220 \, g 
eq 90 \, g$,they do not have the same mass.$(b)$ Molar mass of $Ca = 40 \, g \, mol^{-1}$.Moles of $Ca = \frac{240 \, g}{40 \, g \, mol^{-1}} = 6 \, mol$.Molar mass of $Mg = 24 \, g \, mol^{-1}$.Moles of $Mg = \frac{240 \, g}{24 \, g \, mol^{-1}} = 10 \, mol$.Ratio of moles of $Ca$ to $Mg = 6:10 = 3:5$.

Verify by calculating that:
$(a)$ $5 \, mol$ of $CO_2$ and $5 \, mol$ of $H_2O$ do not have the same mass.
$(b)$ $240 \, g$ of calcium and $240 \, g$ of magnesium elements have a mole ratio of $3:5$.

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Verify by calculating that:$(a)$ $5 \, mol$ of $CO_2$ and $5 \, mol$ of $H_2O$ do not have the same mass.$(b)$ $240 \, g$ of calcium and $240 \, g$ of magnesium elements have a mole ratio of $3:5$.