Van der Waals equation of state is obeyed by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Van der Waals equation for $1$ mole of a real gas is given by $\left( P + \frac{a}{V_m^2} \right) (V_m - b) = RT$,where $V_m$ is the molar vol

Vedclass · Accepted Answer

$\left( P + \frac{n^2 a}{V^2} \right) (V - nb) = nRT$

Vedclass · Answer

(D) The Van der Waals equation for $1$ mole of a real gas is given by $\left( P + \frac{a}{V_m^2} \right) (V_m - b) = RT$,where $V_m$ is the molar volume $(V_m = V/n)$.Substituting $V_m = V/n$ into the equation:$\left( P + \frac{a}{(V/n)^2} \right) (V/n - b) = RT$$\left( P + \frac{n^2 a}{V^2} \right) \left( \frac{V - nb}{n} \right) = RT$Multiplying both sides by $n$ gives the expression for $n$ moles:$\left( P + \frac{n^2 a}{V^2} \right) (V - nb) = nRT$

Van der Waals equation of state is obeyed by real gases. For $n$ moles of a real gas,the expression will be

Similar Questions

At $300 \ K$,the compressibility factor of $1 \ mole$ of a gas is $1.1$. Its pressure is $2.706 \ atm$. What is its volume in $L$? (Given $R=0.082 \ L \ atm \ mol^{-1} \ K^{-1}$).

$A$ $Van \ der \ Waals$ real gas acts as an ideal gas under which of the following conditions?

Explain the compressibility factor $(Z)$.

Under which conditions does a real gas show maximum deviation from ideal gas behavior?

Gases deviate from the ideal gas behaviour because their molecules

Vedclass Test Series

Exam Paper Generator

Online Exam Module