Values of Delta H and Delta S for five differ | vedclass

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(D) For a reaction to be spontaneous at all temperatures,the Gibbs free energy change $\Delta G = \Delta H - T\Delta S$ must be negative at all values

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Reaction $IV$

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(D) For a reaction to be spontaneous at all temperatures,the Gibbs free energy change $\Delta G = \Delta H - T\Delta S$ must be negative at all values of $T$.This condition is satisfied when $\Delta H  0$ (increase in entropy).Looking at the given data:Reaction $I$: $\Delta H > 0, \Delta S > 0$ (Spontaneous at high $T$)Reaction $II$: $\Delta H Reaction $III$: $\Delta H > 0, \Delta S Reaction $IV$: $\Delta H  0$ (Spontaneous at all $T$)Reaction $V$: $\Delta H > 0, \Delta S = 0$ (Non-spontaneous at all $T$)Therefore,Reaction $IV$ is spontaneous at all temperatures.

Similar Questions

For vaporization of water at $1$ atmospheric pressure,the values of $\Delta H$ and $\Delta S$ are $40.63 \ kJ \ mol^{-1}$ and $108.8 \ J \ K^{-1} \ mol^{-1},$ respectively. The temperature when Gibb's energy change $(\Delta G)$ for this transformation will be zero,is ............ $K$. (in $.4$)

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For the reaction $CaCO_{3(s)} \to CaO_{(s)} + CO_{2(g)}$,given $\Delta H^o = 178.3 \, kJ$ and $\Delta S^o = 160 \, J \cdot K^{-1}$. At what temperature will the reaction become spontaneous?

The relation between $\Delta G$ and $\Delta H$ is

For a reaction to occur spontaneously,which of the following conditions must be met?

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Reaction	$\Delta H \ (kJ \ mol^{-1}) / \Delta S \ (J \ K^{-1} \ mol^{-1})$
$I$	$+98.0, +14.8$
$II$	$-55.5, -84.6$
$III$	$+28.3, -17.0$
$IV$	$-40.5, +24.6$
$V$	$+34.7, 0.0$