The value of the universal gas constant $R$ is the same for all gases. What is its physical significance?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The unit of $R$ depends upon the units in which $p$,$V$,and $T$ are measured,as $R = \frac{p \cdot V}{n \cdot T}$.
If pressure is measured in $Pa$ (Pascal),volume per mole is measured in $m^3 \cdot mol^{-1}$,and temperature is measured in $K$ (Kelvin),then the units of $R$ are $Pa \cdot m^3 \cdot K^{-1} \cdot mol^{-1}$,which is equivalent to $J \cdot mol^{-1} \cdot K^{-1}$.
Since $J$ (Joule) defines the unit of work done,$R$ represents the work done by the gas per mole per Kelvin.

Explore More

Similar Questions

$34.05 \ mL$ of phosphorus vapor weighs $0.0625 \ g$ at $546 \ ^oC$ and $0.1 \ bar$ pressure. What is the molar mass of phosphorus (in $g/mol$)?

Two closed vessels of equal volume containing air at pressure $P_1$ and temperature $T_1$ are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at $T_1$ and that in the other at $T_2$,what will be the final pressure in the vessels?

Difficult
View Solution

When an ideal gas undergoes unrestrained expansion,no cooling occurs because the molecules

Calculate the weight of $CH_4$ in a $9 \ L$ cylinder at $16 \ atm$ and $27 \ ^\circ C$ in grams.

Derive the relation between density $(d)$ and molar mass $(M)$ for an ideal gas.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo