Using Young's double slit experiment,a monoch | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for fringe width is $\beta = \frac{D \lambda}{d}$,where $D$ is the distance between the screen and the slits,$\lambda$ is the waveleng

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(D) The formula for fringe width is $\beta = \frac{D \lambda}{d}$,where $D$ is the distance between the screen and the slits,$\lambda$ is the wavelength,and $d$ is the slit separation.Given for the first case:$\lambda_1 = 5000 \,\mathring A$,$d_1 = d$,$\beta_1 = 0.5 \,mm$.So,$\beta_1 = \frac{D \lambda_1}{d} = 0.5 \,mm$ ... $(I)$For the second case:$\lambda_2 = 6000 \,\mathring A$,$d_2 = 2d$,$\beta_2 = ?$So,$\beta_2 = \frac{D \lambda_2}{d_2} = \frac{D 	imes 6000 \,\mathring A}{2d}$ ... $(II)$Dividing $(II)$ by $(I)$:$\frac{\beta_2}{\beta_1} = \frac{D 	imes 6000 \,\mathring A / 2d}{D 	imes 5000 \,\mathring A / d} = \frac{6000}{2 	imes 5000} = \frac{6}{10} = 0.6$Therefore,$\beta_2 = 0.6 	imes \beta_1 = 0.6 	imes 0.5 \,mm = 0.3 \,mm$.

Similar Questions

In Young's double-slit experiment,the intensity at a point is $1/4$ of the maximum intensity. The angular position of this point is:

How is the interference pattern affected when violet light replaces sodium light?

In a Young's double-slit experiment,$92$ fringes are observed when sodium light $(\lambda = 5898 \, \mathring A)$ is used. If light of wavelength $\lambda = 5461 \, \mathring A$ is used instead,how many fringes will be observed?

In a Young's double-slit experiment using a monochromatic source,what is the shape of the interference fringes formed on a screen?

In Young's double slit experiment,the distance between two sources is $0.1 \, mm$. The distance of the screen from the sources is $20 \, cm$. The wavelength of light used is $5460 \, \mathring{A}$. The angular position of the first dark fringe is: (in $^\circ$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module