Using monochromatic light of wavelength lambd | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the thickness of the mica sheet $t = 1.8 	imes 10^{-6} \ m$,refractive index $\mu = 1.6$,and the shift $y = (\mu - 1)t \frac{D}{d}$.The fri

Vedclass · Accepted Answer

$540$

Vedclass · Answer

(B) Given the thickness of the mica sheet $t = 1.8 	imes 10^{-6} \ m$,refractive index $\mu = 1.6$,and the shift $y = (\mu - 1)t \frac{D}{d}$.The fringe width in the first case is $\beta = \frac{\lambda D}{d}$.The fringe width in the third case is $\beta' = \frac{\lambda (2D)}{d} = 2\beta$.Given the condition $y = \beta'$,we have $(\mu - 1)t \frac{D}{d} = 2 \frac{\lambda D}{d}$.Simplifying,we get $(\mu - 1)t = 2\lambda$.Substituting the values: $(1.6 - 1) 	imes 1.8 	imes 10^{-6} = 2\lambda$.$0.6 	imes 1.8 	imes 10^{-6} = 2\lambda$.$1.08 	imes 10^{-6} = 2\lambda$.$\lambda = 0.54 	imes 10^{-6} \ m = 540 \ nm$.

Using monochromatic light of wavelength $\lambda$,an experimentalist sets up the Young's double slit experiment in three ways as shown. If she observes that $y = \beta'$,the wavelength of light used is.....$nm$

Similar Questions

In a $Young's$ double-slit experiment,light of wavelength $6000 \, \mathring{A}$ is used. If the third dark fringe is formed at point $P$ on the screen,then the path difference $(S_1P - S_2P)$ is ......... $\mu m$.

At two points $P$ and $Q$ on the screen in Young's double-slit experiment,waves from slits $S_1$ and $S_2$ have a path difference of $0$ and $\frac{\lambda}{4}$ respectively. The ratio of intensities at $P$ and $Q$ will be

In $YDSE$ experiment,the $4^{\text{th}}$ dark band is formed opposite to one of the slits. The wavelength of light used is ($d=$ distance between the slits,$D=$ distance between source and the screen)

In Young's double-slit experiment using monochromatic light,the shape of the interference pattern on the screen is .....

In $YDSE$,$a=2 \, mm$,$D=2 \, m$,and $\lambda=500 \, nm$. Find the distance of the point on the screen from the central maxima where the intensity becomes $50 \%$ of the central maxima (in $\mu m$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module