Uracil is a base present in RNA with the foll | vedclass

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(C) The molecular formula of uracil is $C_4H_4N_2O_2$.Calculate the molar mass of uracil:$M = (4 	imes 12) + (4 	imes 1) + (2 	imes 14) + (2 	imes

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$25$

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(C) The molecular formula of uracil is $C_4H_4N_2O_2$.Calculate the molar mass of uracil:$M = (4 	imes 12) + (4 	imes 1) + (2 	imes 14) + (2 	imes 16) = 48 + 4 + 28 + 32 = 112 \, g \, mol^{-1}$.The percentage of nitrogen $(N)$ is calculated as:$\% N = \frac{	ext{Mass of } N}{	ext{Molar mass of uracil}} 	imes 100$$\% N = \frac{2 	imes 14}{112} 	imes 100 = \frac{28}{112} 	imes 100 = 25 \%$.

Uracil is a base present in $RNA$ with the following structure. The percentage of $N$ in uracil is $............$.
Given:
Molar mass $N = 14 \, g \, mol^{-1} ; O = 16 \, g \, mol^{-1} ; C = 12 \, g \, mol^{-1} ; H = 1 \, g \, mol^{-1}$.

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Uracil is a base present in $RNA$ with the following structure. The percentage of $N$ in uracil is $............$.Given:Molar mass $N = 14 \, g \, mol^{-1} ; O = 16 \, g \, mol^{-1} ; C = 12 \, g \, mol^{-1} ; H = 1 \, g \, mol^{-1}$.