(N/A) When two plane mirrors are placed at an angle of $90^{\circ}$ to each other,the incident ray and the final reflected ray will always be parallel to each other,regardless of the angle of incidence.
Explanation:
$1$. Let the two mirrors be $M_1$ and $M_2$ placed at $90^{\circ}$.
$2$. The incident ray strikes $M_1$ at an angle of incidence $i$. According to the law of reflection,the angle of reflection $r = i$.
$3$. The reflected ray from $M_1$ acts as the incident ray for $M_2$. By geometry,the angle of incidence at $M_2$ will be $(90^{\circ} - i)$.
$4$. The final angle of reflection at $M_2$ will also be $(90^{\circ} - i)$.
$5$. By calculating the total deviation or the angles with the normal,it can be shown that the final reflected ray is parallel to the initial incident ray.