An ultrasonic signal sent from SONAR returns | vedclass

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(D) The $SONAR$ device sends an ultrasonic signal that travels to the rock and reflects back to the receiver.Let $d$ be the depth of the rock from the

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$800$

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(D) The $SONAR$ device sends an ultrasonic signal that travels to the rock and reflects back to the receiver.Let $d$ be the depth of the rock from the $SONAR$ device.The total distance traveled by the signal is $2d$ (going to the rock and coming back).Given:Velocity of ultrasound $(v)$ = $1600 \, m/s$Total time taken $(t)$ = $1 \, s$Using the formula: $	ext{Distance} = 	ext{Velocity} 	imes 	ext{Time}$$2d = v 	imes t$$2d = 1600 	imes 1$$2d = 1600$$d = \frac{1600}{2} = 800 \, m$.Therefore,the depth of the rock is $800 \, m$.

$A$. Temperature of gas is made $4$ times and pressure $2$ times	$P$. Speed becomes $2\sqrt{2}$ times
$B$. Only pressure is made $4$ times without change in temperature	$Q$. Speed becomes $2$ times
$C$. Only temperature is changed to $4$ times	$R$. Speed remains unchanged
$D$. Molecular mass of the gas is made $4$ times	$S$. Speed becomes half

An ultrasonic signal sent from $SONAR$ returns to it after reflection from a rock after a lapse of $1 \, s$. If the velocity of ultrasound in water is $1600 \, m/s$,the depth of the rock in water is ..... $m$.

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