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(A) Let $a$ be the acceleration of the system. The force $P$ is applied to the block of mass $M$. The total mass of the system is $(M + m)$.According

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$(M + m)g 	an \beta$

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(A) Let $a$ be the acceleration of the system. The force $P$ is applied to the block of mass $M$. The total mass of the system is $(M + m)$.According to Newton's second law,$P = (M + m)a$,so $a = \frac{P}{M + m}$.For the block of mass $m$ to remain stationary with respect to $M$,it must move with the same acceleration $a$ in the horizontal direction.The forces acting on mass $m$ are:$1$. Gravitational force $mg$ acting downwards.$2$. Normal reaction $N$ from the surface of $M$,acting perpendicular to the inclined surface.Resolving the forces on $m$ in the horizontal and vertical directions:Horizontal: $N \sin \beta = ma$Vertical: $N \cos \beta = mg$Dividing the two equations: $\frac{N \sin \beta}{N \cos \beta} = \frac{ma}{mg} \implies 	an \beta = \frac{a}{g} \implies a = g 	an \beta$.Substituting $a$ into the force equation: $P = (M + m)g 	an \beta$.

Two wooden blocks are moving on a smooth horizontal surface such that the mass $m$ remains stationary with respect to the block of mass $M$ as shown in the figure. The magnitude of force $P$ is

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