Two whistles A and B each have a frequency of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Doppler effect formula is given by $n' = n \left( \frac{v \pm v_o}{v \mp v_s} \right)$.For whistle $A$ (source stationary,$v_s = 0$) and obser

Vedclass · Accepted Answer

Both $(B)$ and $(C)$.

Vedclass · Answer

(D) The Doppler effect formula is given by $n' = n \left( \frac{v \pm v_o}{v \mp v_s} ight)$.For whistle $A$ (source stationary,$v_s = 0$) and observer moving away at $25\,m/s$ $(v_o = 25\,m/s)$: $n'_A = 500 \left( \frac{350 - 25}{350} ight) = 500 	imes \frac{325}{350} \approx 464.28\,Hz$.For whistle $B$ (source moving away at $50\,m/s$,$v_s = 50\,m/s$) and observer moving towards it at $25\,m/s$ $(v_o = 25\,m/s)$: $n'_B = 500 \left( \frac{350 + 25}{350 + 50} ight) = 500 	imes \frac{375}{400} = 468.75\,Hz$.Difference in frequencies heard by the observer: $\Delta n = |n'_B - n'_A| = |468.75 - 464.28| = 4.47\,Hz \approx 4.5\,Hz$.Thus,statements $(B)$ and $(C)$ are correct.

Similar Questions

$A$ bus is moving with a velocity of $5 \ m/s$ towards a huge wall. The driver sounds a horn of frequency $165 \ Hz$. If the speed of sound in air is $355 \ m/s$,the number of beats heard per second by a passenger on the bus will be:

$A$ stationary source emits sound waves of frequency $500\, Hz$. Two observers moving along a line passing through the source detect sound to be of frequencies $480\, Hz$ and $530\, Hz$. Their respective speeds are,in $m\,s^{-1}$ (Given speed of sound $= 300\, m/s$)

If the source and the observer are both relatively at rest and the speed of sound is increased,then the frequency heard by the observer will:

Vedclass Test Series

Exam Paper Generator

Online Exam Module