Two vessels are filled with ideal gases A and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Initial state for gas $A$: $P_1 = 8 \ atm$,$V_1 = 12 \ L$. Total volume after opening the stop cock: $V_{total} = 12 \ L + 8 \ L = 20 \ L$.Since t

Vedclass · Accepted Answer

$4.8, 2.0$

Vedclass · Answer

(D) Initial state for gas $A$: $P_1 = 8 \ atm$,$V_1 = 12 \ L$. Total volume after opening the stop cock: $V_{total} = 12 \ L + 8 \ L = 20 \ L$.Since the temperature is constant,we use Boyle's Law $(P_1V_1 = P_2V_2)$ for each gas independently.For gas $A$: $8 \ atm 	imes 12 \ L = P_A 	imes 20 \ L \implies P_A = \frac{96}{20} = 4.8 \ atm$.For gas $B$: $5 \ atm 	imes 8 \ L = P_B 	imes 20 \ L \implies P_B = \frac{40}{20} = 2.0 \ atm$.Thus,the partial pressures of $A$ and $B$ are $4.8 \ atm$ and $2.0 \ atm$ respectively.

Two vessels are filled with ideal gases $A$ and $B$ and are connected through a pipe of zero volume as shown in the figure. The stop cock is opened and the gases are allowed to mix homogeneously and the temperature is kept constant. The partial pressures of $A$ and $B$ respectively (in $atm$) are:

Similar Questions

An air tank has a volume of $10 \, L$ and is filled with air at a pressure of $200 \, atm$. If an adult human breathes in $0.50 \, L$ of air per breath at $1 \, atm$ pressure and $37 \, ^\circ C$,how many breaths can be taken from this tank? (Assume temperature remains constant)

$A$ certain mass of a gas occupies a volume of $250 \ mL$ at $2 \ atm$ pressure. Calculate the volume of the gas if the pressure is increased to $2.5 \ atm$ at a constant temperature. (in $mL$)

Explain: Gay-Lussac's Law.

The ratio of densities of two gases is $1 : 2$. If the ratio of their temperatures is $2 : 1$,find the ratio of their corresponding pressures. (Assume the molar masses of the gases are equal.)

The equation for Boyle's law is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module