Two vessels A and B of 1 , L each contain 0.1 | vedclass

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(A) According to Avogadro's Law,under the same conditions of pressure,temperature,and volume,the number of moles of different gases must be equal.$n_A

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$CO$

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(A) According to Avogadro's Law,under the same conditions of pressure,temperature,and volume,the number of moles of different gases must be equal.$n_A = n_B$$\frac{w_A}{M_A} = \frac{w_B}{M_B}$Given $w_A = 0.11 \, g$ $(CO_2)$,$M_A = 44 \, g/mol$,and $w_B = 0.07 \, g$ (unknown gas).$\frac{0.11}{44} = \frac{0.07}{M_B}$$M_B = \frac{0.07 	imes 44}{0.11} = \frac{7 	imes 44}{11} = 7 	imes 4 = 28 \, g/mol$.The molar mass of the unknown gas is $28 \, g/mol$.Checking the options:$CO$: $12 + 16 = 28 \, g/mol$.$CO_2$: $12 + 32 = 44 \, g/mol$.$C_2H_6$: $2(12) + 6(1) = 30 \, g/mol$.Since $CO$ has a molar mass of $28 \, g/mol$,the unknown gas is $CO$.

Two vessels $A$ and $B$ of $1 \, L$ each contain $0.11 \, g$ $CO_2$ gas and $0.07 \, g$ of unknown gas respectively under the same conditions of pressure and temperature. The unknown gas is:

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