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(D) Let the two wires be placed parallel to the $z$-axis in the $xz$-plane,located at $x = d/2$ and $x = -d/2$. The currents are $I$ (at $x = d/2$) an

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(D) Let the two wires be placed parallel to the $z$-axis in the $xz$-plane,located at $x = d/2$ and $x = -d/2$. The currents are $I$ (at $x = d/2$) and $-I$ (at $x = -d/2$). The point charge $q$ is at the origin $(0,0,0)$,which is equidistant from both wires. The magnetic field $B_1$ due to the first wire at the origin is directed along the $y$-axis. The magnetic field $B_2$ due to the second wire at the origin is also directed along the $y$-axis. The net magnetic field $B = B_1 + B_2$ is directed along the $y$-axis. The velocity $v$ of the charge is given as perpendicular to the plane of the wires (the $xz$-plane),meaning $v$ is directed along the $y$-axis. The magnetic force is given by $F = q(v 	imes B)$. Since both $v$ and $B$ are directed along the $y$-axis,they are parallel to each other. The cross product of two parallel vectors is zero,so $v 	imes B = 0$. Therefore,the magnitude of the magnetic force $F = 0$.

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