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(A) Let the speed of train $A$ be $x \, km/h$.Then,the speed of train $B$ is $(x + 27) \, km/h$.Since they are moving towards each other,their relativ

Vedclass · Accepted Answer

$45$

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(A) Let the speed of train $A$ be $x \, km/h$.Then,the speed of train $B$ is $(x + 27) \, km/h$.Since they are moving towards each other,their relative speed is the sum of their individual speeds: $(x + x + 27) \, km/h = (2x + 27) \, km/h$.The total distance covered by both trains in $16 \, h$ is $1872 \, km$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$,we have:$16(2x + 27) = 1872$Divide both sides by $16$:$2x + 27 = 117$$2x = 117 - 27$$2x = 90$$x = 45 \, km/h$.Thus,the speed of train $A$ is $45 \, km/h$.

Two trains $A$ and $B$ start at the same time from Delhi and Patna respectively towards each other. They meet after $16 \, h$. If the distance between Delhi and Patna is $1872 \, km$ and train $B$ runs $27 \, km/h$ faster than train $A$,what is the speed of train $A$ in $km/h$?

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