Two trains,each of length 90, m, run on paral | vedclass

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(C) Let the speed of the faster train be $v_1$ and the speed of the slower train be $v_2$ in $m/s$.Total length of both trains $= 90 + 90 = 180\, m$.W

Vedclass · Accepted Answer

$15, 5$

Vedclass · Answer

(C) Let the speed of the faster train be $v_1$ and the speed of the slower train be $v_2$ in $m/s$.Total length of both trains $= 90 + 90 = 180\, m$.When moving in the same direction,relative speed $= v_1 - v_2$.Time taken $= \frac{	ext{Total distance}}{	ext{Relative speed}} \implies 18 = \frac{180}{v_1 - v_2} \implies v_1 - v_2 = 10\, (i)$.When moving in opposite directions,relative speed $= v_1 + v_2$.Time taken $= \frac{	ext{Total distance}}{	ext{Relative speed}} \implies 9 = \frac{180}{v_1 + v_2} \implies v_1 + v_2 = 20\, (ii)$.Adding equations $(i)$ and $(ii)$:$2v_1 = 30 \implies v_1 = 15\, m/s$.Subtracting $(i)$ from $(ii)$:$2v_2 = 10 \implies v_2 = 5\, m/s$.Thus,the speeds are $15\, m/s$ and $5\, m/s$.

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