Two stones are projected with the same speed | vedclass

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Question

$\frac{\mathrm{h}_{2}}{\mathrm{h}_{1}}=\frac{\mathrm{u}^{2} \sin ^{2} 	heta_{2}}{2 \mathrm{g}} 	imes \frac{2 \mathrm{g}}{\mathrm{u}^{2} \sin ^{2}

Vedclass · Accepted Answer

$h_1/3$

Vedclass · Answer

$\frac{\mathrm{h}_{2}}{\mathrm{h}_{1}}=\frac{\mathrm{u}^{2} \sin ^{2} 	heta_{2}}{2 \mathrm{g}} 	imes \frac{2 \mathrm{g}}{\mathrm{u}^{2} \sin ^{2} 	heta_{1}}$

$=\frac{\sin ^{2} 	heta_{2}}{\sin ^{2} 	heta_{1}}=\frac{\sin ^{2} \pi / 6}{\sin ^{2} \pi / 3}=\frac{1}{3}$

$	herefore \quad \mathrm{h}_{2}=\mathrm{h}_{1} / 3$

Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is $\pi /3$ and its maximum height is $h_1$ then the maximum height of the other will be

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