Two stations A and B are 100 , km apart on a | vedclass

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(D) $1$. The distance between stations $A$ and $B$ is $100 \, km$.$2$. The train from $A$ starts at $7 \, am$ and travels at $20 \, km/h$. By $8 \, am

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None of these

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(D) $1$. The distance between stations $A$ and $B$ is $100 \, km$.$2$. The train from $A$ starts at $7 \, am$ and travels at $20 \, km/h$. By $8 \, am$,it has traveled for $1 \, hour$,covering $20 \, km 	imes 1 \, h = 20 \, km$.$3$. At $8 \, am$,the remaining distance between the two trains is $100 \, km - 20 \, km = 80 \, km$.$4$. Since the trains are moving towards each other,their relative speed is $20 \, km/h + 25 \, km/h = 45 \, km/h$.$5$. The time taken to meet after $8 \, am$ is $	ext{Time} = \frac{	ext{Distance}}{	ext{Relative Speed}} = \frac{80 \, km}{45 \, km/h} = \frac{16}{9} \, hours = 1 \, hour \, 46 \, minutes \, 40 \, seconds$.$6$. Therefore,the meeting time is $8:00 \, am + 1 \, hour \, 46 \, minutes \, 40 \, seconds = 9:46:40 \, am$.$7$. Since $9:46:40 \, am$ is not among the options,the correct choice is $D$.

Two stations $A$ and $B$ are $100 \, km$ apart on a straight line. One train starts from $A$ at $7 \, am$ and travels towards $B$ at $20 \, km/h$ speed. Another train starts from $B$ at $8 \, am$ and travels towards $A$ at $25 \, km/h$ speed. At what time will they meet?

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