Two statements are given below:
Statement-$I$: Liquids $A$ and $B$ form a non-ideal solution with positive deviation. The interactions between $A$ and $B$ are weaker than $A-A$ and $B-B$ interactions.
Statement-$II$: For an ideal solution,$\Delta_{mix} H = 0$ and $\Delta_{mix} V = 0$.
The correct answer is:

  • A
    Both Statement-$I$ and Statement-$II$ are correct.
  • B
    Both Statement-$I$ and Statement-$II$ are not correct.
  • C
    Statement-$I$ is correct but Statement-$II$ is not correct.
  • D
    Statement-$I$ is not correct but Statement-$II$ is correct.

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Similar Questions

Which of the following is a non-ideal solution?

At $363 \ K,$ the vapour pressure of $A$ is $21 \ kPa$ and that of $B$ is $18 \ kPa$. One mole of $A$ and $2 \ moles$ of $B$ are mixed. Assuming that this solution is ideal,the vapour pressure of the mixture is $....... \ kPa$. (Round off to the Nearest Integer).

Liquid $M$ and liquid $N$ form an ideal solution. The vapour pressures of pure liquids $M$ and $N$ are $450 \ mmHg$ and $700 \ mmHg,$ respectively at the same temperature. Then the correct statement is: ( $x_M =$ mole fraction of $M$ in solution; $x_N =$ mole fraction of $N$ in solution; $y_M =$ mole fraction of $M$ in vapour phase; $y_N =$ mole fraction of $N$ in vapour phase)

What is meant by positive and negative deviations from Raoult's law and how is the sign of $\Delta_{mix} H$ related to positive and negative deviations from Raoult's law?

Which of the following pairs does not form an ideal solution?

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