Two stars $P$ and $Q$ are observed at night. Star $P$ appears reddish while star $Q$ is white. From this we conclude:

  • A
    Temperature of $Q$ is higher than that of $P$
  • B
    Temperature of $Q$ is lower than that of $P$
  • C
    Star $Q$ is at the same distance as that of star $P$
  • D
    Star $P$ is farther than star $Q$

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The wavelength of maximum emission from a body at a temperature of $200 \, K$ is $14 \, \mu m$. If the temperature of the body is increased to $1000 \, K$,find the new wavelength of maximum emission.

Two bodies $A$ and $B$ have emissivities $0.01$ and $0.81$ respectively. The outer surface areas of both bodies are the same. Both bodies emit total radiant power at the same rate. The wavelength $\lambda_B$ corresponding to the maximum spectral radiance of $B$ is $1.0 \mu m$. If the temperature of $A$ is $5802 \ K$,calculate the wavelength $\lambda_A$ in $\mu m$. (Note: The original question asked for $\lambda_B$ but provided $\lambda_B$ as $1.0 \mu m$ and asked for $\lambda_A$ based on the context of the solution provided).

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The wavelength of maximum emission of radiation from a body at $2000 \ K$ is $4 \ \mu m$. What is the wavelength of maximum emission of radiation from the body at $2400 \ K$ in $\mu m$?

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