Two solids dissociate as follows:A_{(s)} righ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the partial pressure of $B_{(g)}$ be $P_1$ and $E_{(g)}$ be $P_2$.From the first equilibrium: $A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$,t

Vedclass · Accepted Answer

$2 \sqrt {x + y} \, atm$

Vedclass · Answer

(A) Let the partial pressure of $B_{(g)}$ be $P_1$ and $E_{(g)}$ be $P_2$.From the first equilibrium: $A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$,the partial pressure of $C_{(g)}$ contributed by this reaction is $P_1$.From the second equilibrium: $D_{(s)} \rightleftharpoons C_{(g)} + E_{(g)}$,the partial pressure of $C_{(g)}$ contributed by this reaction is $P_2$.Total partial pressure of $C_{(g)} = P_1 + P_2$.$K_{p_1} = P_B \cdot P_C = P_1(P_1 + P_2) = x$$K_{p_2} = P_C \cdot P_E = (P_1 + P_2)P_2 = y$Adding both equations:$x + y = P_1(P_1 + P_2) + P_2(P_1 + P_2) = (P_1 + P_2)(P_1 + P_2) = (P_1 + P_2)^2$So,$(P_1 + P_2) = \sqrt {x + y}$.Total pressure $P_{total} = P_B + P_C + P_E = P_1 + (P_1 + P_2) + P_2 = 2(P_1 + P_2)$.Substituting the value: $P_{total} = 2 \sqrt {x + y} \, atm$.

Two solids dissociate as follows:
$A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$; $K_{p_1} = x \, atm^2$
$D_{(s)} \rightleftharpoons C_{(g)} + E_{(g)}$; $K_{p_2} = y \, atm^2$
The total pressure when both the solids dissociate simultaneously is:

Similar Questions

For the reaction $2A_{(g)} + B_{(g)} \rightleftharpoons 3C_{(g)} + D_{(g)}$,two moles each of $A$ and $B$ were taken into a $1 \ L$ flask. Which of the following must always be true when the system attains equilibrium?

For the reaction $CuSO_4 \cdot 5H_2O_{(s)} \rightleftharpoons CuSO_4 \cdot 3H_2O_{(s)} + 2H_2O_{(g)}$,which of the following is a correct representation?

For the reaction $3A + B \rightleftharpoons 2C + D$,if the equilibrium concentrations of $A, B,$ and $C$ are $0.03 \ M, 0.01 \ M,$ and $0.008 \ M$ respectively,what is the initial concentration of $A$ (in $M$)?

$CH_3COCH_{3(g)} \rightleftharpoons C_2H_{6(g)} + CO_{(g)}$. The initial pressure of $CH_3COCH_3$ is $100 \ mm$. When equilibrium is set up,the mole fraction of $CO_{(g)}$ is $\frac{1}{4}$. Hence,the partial pressure of $CO$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Two solids dissociate as follows:$A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$; $K_{p_1} = x \, atm^2$$D_{(s)} \rightleftharpoons C_{(g)} + E_{(g)}$; $K_{p_2} = y \, atm^2$The total pressure when both the solids dissociate simultaneously is: