Two small spherical balls each carrying a cha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the length of each thread be $L = 3\, m$. The angle between the threads is $120^{\circ}$,so each thread makes an angle $	heta = 60^{\circ}$ w

Vedclass · Accepted Answer

None of the above

Vedclass · Answer

(D) Let the length of each thread be $L = 3\, m$. The angle between the threads is $120^{\circ}$,so each thread makes an angle $	heta = 60^{\circ}$ with the vertical.The distance $r$ between the two charges is given by $r = 2L \sin(60^{\circ}) = 2 	imes 3 	imes \frac{\sqrt{3}}{2} = 3\sqrt{3}\, m$.The electrostatic force $F_e$ between the charges is $F_e = \frac{1}{4\pi\varepsilon_0} \frac{Q^2}{r^2} = 9 	imes 10^9 	imes \frac{(10 	imes 10^{-6})^2}{(3\sqrt{3})^2} = 9 	imes 10^9 	imes \frac{10^{-8}}{27} = \frac{10}{27} \approx 0.37\, N$.In equilibrium,the forces acting on one ball are tension $T$ (along the thread),electrostatic force $F_e$ (horizontal),and weight $mg$ (vertical). However,the mass $m$ is not given. Assuming the question implies the tension is balanced by the horizontal component of the electrostatic force,we look at the force balance: $T \sin(60^{\circ}) = F_e$ and $T \cos(60^{\circ}) = mg$.Given the options provided,there seems to be a discrepancy in the provided solution logic. Re-evaluating: $T \sin(60^{\circ}) = F_e \implies T = \frac{F_e}{\sin(60^{\circ})} = \frac{10/27}{\sqrt{3}/2} = \frac{20}{27\sqrt{3}} \approx 0.427\, N$. None of the options match this result. Given the provided solution structure in the prompt,it appears the question is flawed or missing mass information.

Similar Questions

Write the expression for the Coulombian force acting between two point charges kept in a medium.

$A$ charge $Q$ is divided into two charges $q$ and $Q-q$. The value of $q$ such that the force between them is maximum,is

Two point charges $q_2 = 3 \times 10^{-6} \ C$ and $q_1 = 5 \times 10^{-6} \ C$ are located at $B(3, 5, 1) \ m$ and $A(1, 3, 2) \ m$ respectively. Find the magnitude of the force on $q_1$ due to $q_2$.

$A$ certain charge $2Q$ is divided at first into two parts $q_{1}$ and $q_{2}$. Later,the charges are placed at a certain distance. If the force of interaction between the two charges is maximum,then find the value of $\frac{Q}{q_{1}}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module