Two small spheres of masses M_{1} and M_{2} a | vedclass

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(B) For sphere $1$,in equilibrium:$T_{1} \cos 	heta_{1} = M_{1} g$$T_{1} \sin 	heta_{1} = F$Dividing the two equations,we get:$	an 	heta_{1} = \fr

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$M_{1}=M_{2}$

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(B) For sphere $1$,in equilibrium:$T_{1} \cos 	heta_{1} = M_{1} g$$T_{1} \sin 	heta_{1} = F$Dividing the two equations,we get:$	an 	heta_{1} = \frac{F}{M_{1} g}$Similarly,for sphere $2$,in equilibrium:$T_{2} \cos 	heta_{2} = M_{2} g$$T_{2} \sin 	heta_{2} = F$Dividing the two equations,we get:$	an 	heta_{2} = \frac{F}{M_{2} g}$Here,$F$ is the electrostatic force of repulsion between the two spheres,which is the same for both spheres according to Newton's third law.If $	heta_{1} = 	heta_{2}$,then $	an 	heta_{1} = 	an 	heta_{2}$.Therefore,$\frac{F}{M_{1} g} = \frac{F}{M_{2} g}$,which implies $M_{1} = M_{2}$.

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