Two small blocks slide without losing contact | vedclass

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(B) The correct answer is $B$.$1$. For block $1$,the velocity remains constant at $v$ throughout the motion because the track is horizontal and fricti

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Block on track $2$ reaches the finish line first.

Vedclass · Answer

(B) The correct answer is $B$.$1$. For block $1$,the velocity remains constant at $v$ throughout the motion because the track is horizontal and frictionless.$2$. For block $2$,as it enters the dip,it gains potential energy which is converted into kinetic energy. Thus,its speed increases beyond $v$ while it is in the dip.$3$. After passing the dip,the block returns to its original speed $v$ as it climbs back up to the horizontal level.$4$. Since block $2$ travels a portion of the track with a speed greater than $v$,its average speed over the entire distance is greater than the constant speed $v$ of block $1$.$5$. Consequently,block $2$ covers the same total horizontal distance in less time than block $1$.

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