Two similar tiny balls of mass $m$,each carrying charge $q$,are hung from silk threads of length $l$ as shown in the figure. These are separated by a distance $x$ and the angle $2\theta$ is small. Then,for equilibrium:

  • A
    $x = 2l$
  • B
    $x = \frac{lq^2}{4\pi\varepsilon_0 mg}$
  • C
    $x = \left(\frac{q^2 mg}{4\pi\varepsilon_0}\right)^{1/2}$
  • D
    $x = \left(\frac{q^2 l}{2\pi\varepsilon_0 mg}\right)^{1/3}$

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$A$ paisa coin is made up of $Al-Mg$ alloy and weighs $0.75\,g$. It is electrically neutral and contains equal amounts of positive and negative charge of magnitude $34.8\,kC$. Suppose that these equal charges were concentrated in two point charges separated by:
$(i)$ $1\,cm$ $(\sim \frac{1}{2} \times \text{diagonal of the one paisa coin})$
$(ii)$ $100\,m$ $(\sim \text{length of a long building})$
$(iii)$ $10^6\,m$ $(\text{radius of the earth})$.
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