(A) Yes,the two triangles are similar.
Let the sides of the first triangle be $a_1, b_1, c_1$ and its perimeter be $P_1 = a_1 + b_1 + c_1$.
Let the sides of the second triangle be $a_2, b_2, c_2$ and its perimeter be $P_2 = a_2 + b_2 + c_2$.
Given that $a_1 = 3a_2$,$b_1 = 3b_2$,and $P_1 = 3P_2$.
Since $P_1 = a_1 + b_1 + c_1$ and $P_2 = a_2 + b_2 + c_2$,we have $3P_2 = 3a_2 + 3b_2 + c_1$.
Substituting $P_2 = a_2 + b_2 + c_2$,we get $3(a_2 + b_2 + c_2) = 3a_2 + 3b_2 + c_1$,which simplifies to $3c_2 = c_1$.
Since all three corresponding sides are proportional $(\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} = 3)$,by the $SSS$ similarity criterion,the two triangles are similar.